What does \(\sum_{n\in\mathbb N}\frac{n^x}{x^n}\) converge to when \(x\in\mathbb R^+\) and \(x>1\)?
\(\sum_{n\in\mathbb N}\frac{n^x}{x^n}\)
Yes, I forget this isn't M.SE. :)
just so i can read it, i don't know it
i think if you use \[ instead of \( it will work
I fixed it, refresh. The "\(" is for inline equations.
aah now i can see it dollar signs don't work here for some reason
I'm just trying to make sure this question is M.SE material before I post it, aha. Maybe it has a trivial solution I'm missing.
is it supposed to be something nice?
Not sure.
It's so tiny I can'r even read it.
\[\huge \sum_{n\in\mathbb N}\frac{n^x}{x^n}\]
@satellite73 I'm not sure what \(\large n \in \mathbb N\) means :|
\(n\) is natural. \(x\) is positive reals.
So basically to infinity....yes ?
Yes.
Ohh ok. Just to make sure... \[\large \sum_{n=1}^{\infty} \frac{n^x}{x^n}\]Yeah im not sure if n would start at 0 or1....
@mathstudent55 ? :\
n starts at 1.
n E N just means n is all natural numbers
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