y varies inversely as twice x. When x = 2, y = 3. Find y when x = 6
If y varies inversely with 2x, then \[y = \frac{k}{2x}\]where \(k\) is the constant of variation. Plug in your known values to determine the value of \(k\), then use the updated equation to find y when x = 6
i dont know where to even start.
Take my equation. Plug in the values in the "when " statement. Solve for k. Replace k in my equation with the number you got. Plug in the value of x from the "find y when" statement and, well, find y! :-)
do you understand how/why I wrote that equation?
ya hold up im working the problem out
np, I'll get a notification when you respond...
ya i cant figure it out..
okay, we know x=2, y = 3 \[y = \frac{k}{2x}\]\[3=\frac{k}{2*2}\]Solve that for \(k\)
k is the number that when divided by 4 gives you 3. what is k?
dude, are you like growing some extra fingers to work it out, or what?
6?
6 divided by 4 gives you 3?
no buyt my options is 1, 2, 4, or 6
we aren't done yet! we're trying to find k, which you need to find the answer.
you shouldn't need to make any reference to the answer key to work this problem out with 100% certainty.
so, I ask again, what number, divided by 4, equals 3?
12
right! now, we know that k=12, so our equation becomes \[y = \frac{12}{2x}\]All we have to do to get the answer for the problem is plug in the value of x for which they want to know the value of y.
y=6?
so x=1?
Yes, x = 1. Here's a picture:
You can see that when x=2, y = 3, and when x = 6, y = 1 (y, not x)
and that's the curve shape you get with inverse variation
so the final answer is 1
yes.
thank you.
you're welcome.
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