9a^2+24ab+16b^2 Factoring
Try to write the given expression in the form of \(a^2 - 2ab + b^2\)
It is
Not perfectly. We need to simplify it more. Like, writing 9a^2 as (3a)^2 ...
So 3a^2+8ab+4a^2?
No, first of all, don't forget to put brackets : \((3a^2) + 8ab + (4b)^2 \) Now, the second term is wrong, we had 24ab and you have written 8ab, we can write it as : \(24ab = 2(3a)(4b)\) \(\implies (3a)^2 + 2(3a)(4b) + (4b)^2\)
Wait so the bottom equation is the answer?
Now, compare it with : \(a^2 + 2ab + b^2\) You get , a = 3a, b = 4b... Since, \(a^2+ 2ab + b^2 = (a+b)^2\) Therefore, \((3a)^2 + 2(3a)(4b) + ( 4b)^2 = (3a+4b)^2 \textbf{or} ~ (3a+4b)(3a+4b)\)
That is not the answer, it was yet to be factored ...
Ah this why i failed the class the first time. lol. So from (3a+4b)(3a+4b)
Yes that is the answer now.
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