Question

Determine the extreme values of this function on the given interval.
f(x)= 1+ (x+3)² ; -2 12 years ago

Answer 1

Calc or pre-calc?

Answer 2

pre-cal @SithsAndGiggles

Answer 3

Ok, that method's a bit less work.

So you're given a parabola in vertex form:
\[f(x)=1+(x+3)^2\]
\(f(x)\) has vertex (an extreme value point) at \((-3,1)\). \(-3\) is not in the interval \(-2<x<6\).
So, you have something that looks like this:

This means that only the endpoints of this interval will contain the extreme values.