The regular price of a child's entry ticket to a water park is $6 less than that for an adult's. The park offers half off of all entry tickets during the off-peak season. The Jordans paid a total of $69 for 2 adult tickets and 1 child's ticket to the water park during the off-peak season. The following equation represents this situation, where x represents the regular price of an adult ticket. 69 = x + one-half(x - 6) What is the regular price of a child's ticket?
someone help my brain hurts im sleepy ! please?!?
\[69 = x + \frac{x-6}{2}\]Why not start by multiplying everything by 2 to get rid of the fraction?
So child = Adult - 6, off peak pricing = 1/2(peak pricing), total off peak pricing = (2*adult) + (1*child) => (2*adult)+(1(adult-6)) If 'x' is the 'adult' and 69 is the total peak pricing, then your equation looks like \(69 = 2x+1(x-6)\) multiply your answer by 2 to get the peak price of an adult, less 6 for a peak price of child.
Once you've solved that for \(x\) remember that \(x\) is the price of an adult ticket, and you want the price of a child's ticket, which is $6 less than an adult ticket. Don't get tripped at the finish line :-)
His equation was incorrect, it did not take into account the discount for all tickets.
or, her equation. :)
yes, actually it does. 69 = 2* adult + 1 * kid these prices are off-peak, so they cost 50% less, and they've just collapsed 2*50% into x and kid/2
Except that 69 is the discounted total.
Sigh. Let Af be the price of a full-price adult ticket. Cf is the price of a full-price child ticket, and = Af - 6. Ad is the price of a discount adult ticket, and = Af/2. Cd is the price of a discount child ticket, and = Cf/2 = (Af-6)/2. They bought 2 adult discount tickets and 1 child discount ticket and paid $69. $69 = 2*Ad + Cd = 2*(Af/2) + (Cf/2) = Af + (Af-6)/2 Now replace Af with x and you have...the equation from the problem statement.
I stand corrected.
I scratched my head a few times looking at it when I first read it, too!
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