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OpenStudy (anonymous):
OpenStudy (anonymous):
A
OpenStudy (anonymous):
B
OpenStudy (anonymous):
C
OpenStudy (anonymous):
D
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OpenStudy (whpalmer4):
Okay, first thing to note is that the parabola opens to the side, not up or down, so it will be of the form y^2 = x rather than y = x^2
OpenStudy (whpalmer4):
This means, by the way, that the relationship is not a function, because we can draw a vertical line that crosses the curve more than once.
OpenStudy (anonymous):
ok got that
OpenStudy (anonymous):
how can you tell which answer is correct?
OpenStudy (whpalmer4):
Well, we can eliminate any that have x being squared — we need equations where y is squared.
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OpenStudy (anonymous):
D is out
OpenStudy (anonymous):
leaves a,b,c
OpenStudy (whpalmer4):
\[(x-3)=-(y+2)^2\]
ok
\[(x+4)=(y+1)^2\]
ok
\[(x+7)^2=(y+2)\]
not ok
\[(x+3)=(y+1)^2\]
ok
OpenStudy (whpalmer4):
Now, can you tell me the vertex of the parabola?
OpenStudy (whpalmer4):
brb, I'm cooking dinner
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OpenStudy (anonymous):
no i cant. can i just get the answer and explain it after?
OpenStudy (anonymous):
i think C
OpenStudy (whpalmer4):
the vertex is the point at the bottom of the bowl.
OpenStudy (anonymous):
because -3,-1
OpenStudy (whpalmer4):
or the end, as the case may be
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OpenStudy (anonymous):
its like where the graph is at so is that the answer?
OpenStudy (anonymous):
i mean parabola
OpenStudy (whpalmer4):
looks like (-4,-1) to me, do you agree?
OpenStudy (anonymous):
oh yes i see it now. B fulfills it
OpenStudy (whpalmer4):
that vertical line is the directrix, and the dot is the focus, they are symmetric about the vertex (same distance away)
the vertex is an obvious point to try in the equations.
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