Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

How do you go from standard form to vertex form?

jimthompson5910 (jim_thompson5910):

do you have an example to work with?

OpenStudy (anonymous):

Completing the square, assuming you're talking about a parabola.

OpenStudy (anonymous):

y = 3x2 + 19x – 40

jimthompson5910 (jim_thompson5910):

ok step 1 is to find the x coordinate of the vertex

jimthompson5910 (jim_thompson5910):

you use this formula x = -b/(2a) in this case a = 3 b = 19

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (anonymous):

-19/6

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

now that you know the x coordinate of the vertex, you plug this into the original equation to find the y coordinate of the vertex

jimthompson5910 (jim_thompson5910):

y = 3x^2 + 19x – 40 y = 3(-19/6)^2 + 19(-19/6) – 40 .... .... .... y = ???

OpenStudy (anonymous):

-841/12 ??

jimthompson5910 (jim_thompson5910):

you got it

jimthompson5910 (jim_thompson5910):

so the equation \[\large y = 3x^2 + 19x - 40\] turns into \[\large y = 3\left(x + \frac{19}{6}\right)^2 - \frac{841}{12}\] after completing the square

jimthompson5910 (jim_thompson5910):

remember that after completing the square and getting an equation into vertex form, you will have this basic form y = a(x-h)^2 + k where (h,k) is the vertex

OpenStudy (anonymous):

Thank you so much! Do you think you could do another example?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

y = 2x2 - 12x + 22

jimthompson5910 (jim_thompson5910):

a = ?? b = ??

OpenStudy (anonymous):

a= 2 b=-12

jimthompson5910 (jim_thompson5910):

x = -b/(2a) x = ??

jimthompson5910 (jim_thompson5910):

to be technical, it should be h = -b/(2a) h = ??

OpenStudy (anonymous):

h=3

jimthompson5910 (jim_thompson5910):

this is the x coordinate of the vertex (and the axis of symmetry)

jimthompson5910 (jim_thompson5910):

plug it into the original equation to find the y coordinate of the vertex (ie the value of k)

jimthompson5910 (jim_thompson5910):

throughout this whole process, 'a' stays the same and it is a = 2 in this case

OpenStudy (anonymous):

-40=y

jimthompson5910 (jim_thompson5910):

no, that's not correct

OpenStudy (anonymous):

4

jimthompson5910 (jim_thompson5910):

y = 2x^2-12x+22 y = 2(3)^2-12(3)+22 y = 4 correct

OpenStudy (anonymous):

so vertex = (3,4)

jimthompson5910 (jim_thompson5910):

x coordinate of the vertex is 3 ----> h = 3 y coordinate of the vertex is 4 ----> k = 4

jimthompson5910 (jim_thompson5910):

a = 2 (given) h = 3 (just found this) k = 4 (just found this) y = a(x-h)^2 + k ... vertex form y = 2(x-3)^2 + 4 ... plug in a = 2, h = 3, k = 4 so 2x^2-12x+22 converts to y = 2(x-3)^2 + 4 which is now in vertex form

OpenStudy (anonymous):

THANK YOU SO MUCH! this helps tremendously! It's actually not that hard!

jimthompson5910 (jim_thompson5910):

nope it's not too bad once you know a handy formula you could go another route and complete the square, but that gets ugly sometimes

OpenStudy (anonymous):

yeah that one is really confusing....I'll stick with this one:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!