Question

Find any critical numbers of the function.
(sin(x))^2 + cos(x) ) 0 < x < 2π

Answer 1

Were you able to find the derivative function?

Answer 2

not sure if its correct : 2 (sin x) (cos x) - sin x ?

Answer 3

Yah looks good :)

Answer 4

ok then what? hehe

Answer 5

Critical points exist where lines tangent to our function are horizontal.
Or in other words, when our derivative function is zero.

\[\large 2\sin x \cos x - \sin x=0\]

So we let our function equal zero like this, and solve for x.

Answer 6

If we factor a sin x out of each term, it gives us,\[\large \sin x(2\cos x-1)=0\]right? :o

Answer 7

yupp i got it now i know what to do ! thanks !

Answer 8

ok cool :)

Answer 9

thanks!