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Evaluate the integral e^-0.01x-6 dx from 0 to 100
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Is the -6 in the exponent?
yes
\[\large \int\limits_0^{100}e^{(-0.01x-6)}dx\] Using laws of exponents, we can rewrite our exponential like so,\[\large e^{(-0.01x-6)} \qquad = \qquad e^{-0.01x}\cdot e^{-6}\] Notice that e^{-6} is a constant with respect to x, so we can simply pull it out of the integral, giving us,\[\large e^{-6}\int\limits_0^{100}e^{-0.01x}dx\] Understand what I did so far?
yes I do
Do you understand how to evaluate this integral? \[\large \int\limits e^{2x}dx\]
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I think so. Is the answer -100/e^7 + 100/e^6 ?
Yes, very good! :)
thank you!
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