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MIT 6.002 Circuits and Electronics, Spring 2007 8 Online
OpenStudy (anonymous):

Final Exam 2013 edx 6.002x Q1 In this problem, we look at the design of an inverter. For the entirety of this problem Vs=50 , and all transistors are modeled with the SR model with Ron=80 We design the inverter shown in Figure 1.

OpenStudy (anonymous):

The static discipine of the inverter is Vil=1.5V ,Vol=1V , Vih=3.4V, Voh=4V , and . What is the minimum resistance (in Ohms) that can be to meet this static discipline?

OpenStudy (anonymous):

Vil<Vt<=Vih Vs*(Ron/(Rl+Ron)<=Vol

OpenStudy (anonymous):

@kai.kai.beyblade @Kuba222 have u solved Q1 Q2

OpenStudy (anonymous):

NO !

OpenStudy (anonymous):

@abdullatif92211 Did you got any of the answers?

OpenStudy (anonymous):

not yet.. just trying to solve those... wat about u?? @kai.kai.beyblade

OpenStudy (anonymous):

oh! even I started to solve! but I'm really screwed ! O.o @abdullatif92211

OpenStudy (anonymous):

plz list all the questions here we will try togather

OpenStudy (anonymous):

give me Q2 & 5 answers

OpenStudy (anonymous):

Guys! Q3:: any one have the answer for Q3? The circuits in this problem are driven by sinusoidal sources and are in the steady state. For each circuit, enter the letter corresponding to its magnitude and phase plot for the transfer funrction H(jw) =V0(jw)/Vi(jw) from the magnitude (A-F) and phase (G-L) plots sketched in the figures below. The magnitude plots are on a log-log scale and the phase plots are on a linear-log scale. Note these are sketches, look for correct approximate shape

OpenStudy (anonymous):

what are qs?

OpenStudy (anonymous):

cope ur figure paste here

OpenStudy (anonymous):

or save ur figure as picture and then attach here in below menu

OpenStudy (anonymous):

OpenStudy (anonymous):

@fazal7 done!

OpenStudy (anonymous):

plz anybody give answers of any Question.............

OpenStudy (anonymous):

all of us guys should post the solutions here along parameters.

OpenStudy (anonymous):

@Kuba222 tell me at least solution of one Question

OpenStudy (anonymous):

Guys!! open up! put your answers here! Help needed badly!

OpenStudy (anonymous):

plz anybody tell me at least one solution of any question

OpenStudy (anonymous):

kaha gae sab bhai

OpenStudy (anonymous):

hahahahaha kai kai dun worry i m trying.. :))

OpenStudy (anonymous):

@abdullatif92211 Thanks mate!

OpenStudy (anonymous):

@Kuba222 I'm trying to get the answers! Once finished I'll write down here, because I've to write the process too!

OpenStudy (anonymous):

@kai.kai.beyblade what u have solved till now??

OpenStudy (anonymous):

q2 part1 ans, id=2mA

OpenStudy (anonymous):

PLZ POST Q3 AND Q4 HERE

OpenStudy (anonymous):

FOR ID USE THIS FORMULA ID=10V-V0/2K -4V/4K

OpenStudy (anonymous):

I USE VALUE OF ABOVE GIVEN Q

OpenStudy (anonymous):

@Tcher Do you have any solutions/?

OpenStudy (anonymous):

guys plz help me with ques 3

OpenStudy (anonymous):

@fazal7 please check the above attached ones!

OpenStudy (anonymous):

Dear All, I've just crossed 60% and left at 63% ! My sincere thanks to @Kuba222, @Tcher and @halfwebprince and special thanks to @fazal7 and @abdullatif92211! With out them I could'nt have reached this milestone. I'm open for Final Qns 1, 2, and 3 Q4 and 5 were typical and left out!.

OpenStudy (anonymous):

Q1 problem 2 ; Tr= -Rl*Cgs*ln((Vs-Voh)/Vs) Q1 problem 5: Tf= -Rth*Cgs*ln((Vol-Vth)/(Vs-Vth)) Hope this will really help you out guys!

OpenStudy (anonymous):

Q1 FULL: Q1 problem 2 ; Tr= -Rl*Cgs*ln((Vs-Voh)/Vs) Q1 problem 5: Tf= -Rth*Cgs*ln((Vol-Vth)/(Vs-Vth)) Q1 Problem 1: Vol= (Vs*Ron)/(Ron+r) Have a blast ;) Q1 Problem 3; Rl||Ron probl 4; Tau= Rth*Cgs, where Rth= Ron||Rl

OpenStudy (anonymous):

Guys! Help others too!! don't get away with only these answers, please do share!! Q4 and Q5 solutions are badly needed!! @Tcher Hope U'll receive the solutions.

OpenStudy (anonymous):

Q1 In this problem, we look at the design of an inverter. For the entirety of this problem VS=7.0V, and all transistors are modeled with the SR model with RON=120Ω. We design the inverter shown in Figure 1. Figure 1 The static discipine of the inverter is VIL=2V, VOL=1V, VIH=5V, and VOH=6V. What is the minimum resistance (in Ohms) that R can be to meet this static discipline? unanswered We now cascade two of these inverters shown in Figure 2. Assume that R=3kΩ. We want to ananlyze the speed of our inverter, so we model the parasitic capacitance at node B as the gate-to-source capacitance of the the second gate, CGS=0.3pF. Figure 2 First we consider the case where the voltage at node B is rising. What is the time (in nanoseconds) after the falling edge at node A, that it takes for the signal at node B to rise from 0V to VOH=6V? unanswered Now we consider the case where the voltage at node B is falling. After the rising edge at node A, what is the Thevenin equivalent resistance (in Ohms) as seen by the gate-to-source capacitance, CGS? unanswered What is the time constant, τf (in picoseconds), for this falling transient voltage? unanswered What is the time (in picoseconds) that it takes for the signal at node B to fall from 7.0V to the value of VOL=1V?

OpenStudy (anonymous):

somebody help me

OpenStudy (anonymous):

plz tell me Q1 part 2 quetion plz tell me the answer?

OpenStudy (anonymous):

R=3Kohm CGS=0.3pf Voh=6v Vol=1v plz tell me the this 4 answers . plzzzzzzzzzz

OpenStudy (anonymous):

what happened?

OpenStudy (anonymous):

Big problem)) need 5% but no idea about Q4 and Q5 at all(((

OpenStudy (anonymous):

Tcher, have you completed that 1st answer?

OpenStudy (anonymous):

yes? yes

OpenStudy (anonymous):

so only 4 and 5 are left?

OpenStudy (anonymous):

i want some formulas? not the answers? if You can? please)

OpenStudy (anonymous):

how much time you have Tcher?

OpenStudy (anonymous):

10 hours)))

OpenStudy (anonymous):

then don't worry. i'll solve that for you tomorrow and post the answer. more than enough time is remaining.

OpenStudy (anonymous):

ok? i solving them too? but have no optimism)))))))))

OpenStudy (anonymous):

if you solve just one question then you'll go pass the 60%

OpenStudy (anonymous):

yes? but i am not at home? in other city? and work by phone)))))

OpenStudy (anonymous):

Can someone help me with question 3 ?

OpenStudy (anonymous):

yes question 3 is easy same for every person.

OpenStudy (anonymous):

But please tell the answers , I dont know

OpenStudy (anonymous):

chaand, i am opening my friends edx account

OpenStudy (anonymous):

I didnt got you :-/

OpenStudy (anonymous):

If u knw answer plz post

OpenStudy (anonymous):

FWCYDX

OpenStudy (anonymous):

i posted that off from my friends edx account.

OpenStudy (anonymous):

Thanks man

OpenStudy (anonymous):

Question 2 ?

OpenStudy (anonymous):

Tcher knows the solution for Q2. ask him.

OpenStudy (anonymous):

Q1 plz

OpenStudy (anonymous):

okay, wajdanaqib. i am giving answers to one guy in chat. come there.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

I cannot come on chat, i m on mobile. Please post question 1 solution over here

OpenStudy (anonymous):

chaand.i, the question differs from person to person. post your question1 parameters here.

OpenStudy (anonymous):

Okay, thanks halfwayprince, I'll tell u once I get access to my desktop. Meanwhile, thanks man.

OpenStudy (anonymous):

chaand.i you can give me medal if you like.

OpenStudy (anonymous):

Take it from me)

OpenStudy (anonymous):

Oh thank you friend. I'll surely give you that 4th or 5th answer as soon as i can.

OpenStudy (anonymous):

Do not thank me, doing a good job)

OpenStudy (anonymous):

and what is wrong?

OpenStudy (anonymous):

(in picoseconds

OpenStudy (anonymous):

formula is correct Tf= -Rth*Cgs*ln((Vol-Vth)/(Vs-Vth))

OpenStudy (anonymous):

WHAT IS Vth

OpenStudy (anonymous):

V Thevenin

OpenStudy (anonymous):

i mean its value? VIL=2.5V, VOL=1.5V, VIH=7.5V, and VOH=8.5V , RON=200Ω ,VS=10.0V What is the time (in picoseconds) that it takes for the signal at node B to fall from 10.0V to the value of VOL=1.5V?

OpenStudy (anonymous):

i donno how to calculate v th here

OpenStudy (anonymous):

Tf= -Rth*Cgs*ln((Vol-Voh)/(Vs-Voh))

OpenStudy (anonymous):

@Tcher part 5 man.... also can u help me with q4 and 5 ??

OpenStudy (anonymous):

i dont know the answers? but .......... working hard)))))))

OpenStudy (anonymous):

Tcher GL

OpenStudy (anonymous):

what is vth?

OpenStudy (anonymous):

Any help please with the new final exam?

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