WARNING: THIS IS A SUPER HARD QUESTION NO ONE CAN SOLVE THIS
\[0^{0}\]
why
would it be 1 ?
tell me why
\[0^0\] is not defined, it is like dividing over zero This is my point of view
no it would be 0 because you are multiplying something by 0 it is 0
IDK why
it stupid
it is an undefined case.
told it was hard
0^0 is not defined
no its not hard. its simple and straight forward
to explain y
it is cunfusing if you dont understand it though
why is it not defined
the 0 as an exponent is like multiplying that # by 1
There is no true consensus on the value of \(0^0\) it is often regarded as undefined, but many mathematicians have adopted the convention of assigning it the value 1, such as Leonard Euler
as we know that 0/0 is an undefined case any number n to the power 0 is n/n = 1 thus 0 power 0 = 0/0 which is undefined
That's a nice argument, but with some analysis using limits and the definition of what it means to divide by zero or raise to a zero exponent the above proof breaks down http://www.faqs.org/faqs/sci-math-faq/specialnumbers/0to0/
thak u
maybe more accessible http://www.askamathematician.com/2010/12/q-what-does-00-zero-raised-to-the-zeroth-power-equal-why-do-mathematicians-and-high-school-teachers-disagree/
sorry for the overload, but yet another explanation: http://mathforum.org/dr.math/faq/faq.0.to.0.power.html I just like to be thorough :) welcome!
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