Question

How many moles are present in an 88 g sample of iron(III)oxide (Fe203)?

Answer 1

F U

Answer 2

can u find out molar mass of Fe2O3

Answer 3

159.69

Answer 4

good:)
159.69 gram of Fe2O3 = 1mole of Fe2O3
then 88 gram of Fe2O3 = X can you find out X

Answer 5

14052.72?

am i multiplying or dividing 88 and 159.69?

Answer 6

cross multiplication u have to do
1*88 =159.69 *X

Answer 7

0.55?

Answer 8

ur right :)