Use the standard enthalpies of formation for the reactants and products to solve for the ΔHrxn for the following reaction. (The ΔHf of Hg2Cl2 is -265.2 kJ/mol and HgCl2 is -224.3 kJ/mol.)

Hg2Cl2 (s) HgCl2 (s) + Hg(l)

ΔHrxn =A. +40.9 kJ
B. -489.5kJ
C. -40.9kJ

The reaction is .
A.exothermic
B.endothermic

Question

Use the standard enthalpies of formation for the reactants and products to solve for the ΔHrxn for the following reaction. (The ΔHf of Hg2Cl2 is -265.2 kJ/mol and HgCl2 is -224.3 kJ/mol.)

Hg2Cl2 (s) HgCl2 (s) + Hg(l)

ΔHrxn =A. +40.9 kJ
              B. -489.5kJ
              C.  -40.9kJ

The reaction is .
A.exothermic
B.endothermic

anonymous · Answer

@summerforever21 you'd be great help.

anonymous · Answer

I think it's +40.9kJ
and that it's exothermic .
But not completely sure .

anonymous · Answer

i am not completely sure about this one either. I think your right but i cant decided if it endo or exo thats all but your right a bout it being +40.9kj

anonymous · Answer

yeah i'm not sure on how to tell if it's endo or exo.. should i try looking it up?

anonymous · Answer

i tried looking it up and it wont tell me anything ..

anonymous · Answer

yeah maybe, not sure if you get good results though. maybe chmvijay can help you

anonymous · Answer

Thankyou (: 
you're always great help.

anonymous · Answer

awhhh :) thank you. your the best, keep up the good work :D

anonymous · Answer

i will(:

anonymous · Answer

it was endothermic (:

anonymous · Answer

good:D

anonymous · Answer

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anonymous · Answer

Just because of your help ahaha(:

anonymous · Answer

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anonymous · Answer

haha thankyou (:

anonymous · Answer

no problem :D Smart can go along way but stupid can only go so far and too me everyone is smart. you may not be as smart as your best friend and you may be smarter than them but everyone is smart in there own way and will find it in there own time.

anonymous · Answer

true(:

anonymous · Answer

lol yep :D

anonymous · Answer

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anonymous · Answer

AWESOME thats great and it not just me who made that happen

anonymous · Answer

you helped alot though(:

anonymous · Answer

awhhh :D thank you.

anonymous · Answer

you're welcome (:

anonymous · Answer

:D good luck

anonymous · Answer

Thankyou(:  i'll be on here again soon ahaha

anonymous · Answer

its a good site too get though so feel freee too come back, ill be here too help

anonymous · Answer

good(:

anonymous · Answer

I love to help people!

anonymous · Answer

i can tell(:

anonymous · Answer

good :D