Find the rectangular coordinates of the point with the polar coordinates (3, 5pi/3)
we know that : \[x=r\cos \theta\\y=r\sin\theta\] OK ?
Okay
3 = rcostheta 5pi/3 = rsintheta
you have : \[r=3\\ \theta=\frac{5\pi}3 \] Right ?
Idk, why is r 3? isnt x and y values 3 and 5pi/3 respectively?
x=0.5 and y=-2.598
by using abov given formulas
0.5 = 3cos(5pi/3) -2.6 = 3sin(5pi/3)
@kjuchiha Listen to me carefully ! You are given the polar coordinates The first of them is r and the second is theta ! Get it ?
ohhh okay! cool
But now what?
x = 3cos(5pi/3) y = 3sin(5pi/3)
cos 5pi/3 =0.5 now muplty 3*0.5 gives 0.5 so x=o.5 same as calculate y give -2.598
So much easier than it looks. Thanks fozia, I've got it now
@kjuchiha Yes
And you Noura! Almost forgot about you lol
You can find exact values : \[x=r\cos\theta=3\cos\frac{5\pi}{3}=3\cos\left(\frac{5\pi}{3}-2\pi\right)=3\cos\frac{-\pi}{3}=3\times\frac12=\frac32\\ y=r\sin\theta=3\sin\frac{5\pi}{3}=3\sin\left(\frac{5\pi}{3}-2\pi\right)=3\sin\frac{-\pi}{3}=3\times\frac{-\sqrt3}2=-\frac{3\sqrt3}2\]
I see! That's kind of what i did after u told me x = rcostheta and y = rsintheta
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