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Mathematics 17 Online
OpenStudy (anonymous):

Find the rectangular coordinates of the point with the polar coordinates (3, 5pi/3)

OpenStudy (anonymous):

we know that : \[x=r\cos \theta\\y=r\sin\theta\] OK ?

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

3 = rcostheta 5pi/3 = rsintheta

OpenStudy (anonymous):

you have : \[r=3\\ \theta=\frac{5\pi}3 \] Right ?

OpenStudy (anonymous):

Idk, why is r 3? isnt x and y values 3 and 5pi/3 respectively?

OpenStudy (fozia):

x=0.5 and y=-2.598

OpenStudy (fozia):

by using abov given formulas

OpenStudy (anonymous):

0.5 = 3cos(5pi/3) -2.6 = 3sin(5pi/3)

OpenStudy (anonymous):

@kjuchiha Listen to me carefully ! You are given the polar coordinates The first of them is r and the second is theta ! Get it ?

OpenStudy (anonymous):

ohhh okay! cool

OpenStudy (anonymous):

But now what?

OpenStudy (anonymous):

x = 3cos(5pi/3) y = 3sin(5pi/3)

OpenStudy (fozia):

cos 5pi/3 =0.5 now muplty 3*0.5 gives 0.5 so x=o.5 same as calculate y give -2.598

OpenStudy (anonymous):

So much easier than it looks. Thanks fozia, I've got it now

OpenStudy (anonymous):

@kjuchiha Yes

OpenStudy (anonymous):

And you Noura! Almost forgot about you lol

OpenStudy (anonymous):

You can find exact values : \[x=r\cos\theta=3\cos\frac{5\pi}{3}=3\cos\left(\frac{5\pi}{3}-2\pi\right)=3\cos\frac{-\pi}{3}=3\times\frac12=\frac32\\ y=r\sin\theta=3\sin\frac{5\pi}{3}=3\sin\left(\frac{5\pi}{3}-2\pi\right)=3\sin\frac{-\pi}{3}=3\times\frac{-\sqrt3}2=-\frac{3\sqrt3}2\]

OpenStudy (anonymous):

I see! That's kind of what i did after u told me x = rcostheta and y = rsintheta

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