Assume that y varies inversely as x. If y = -6 when x = -2, find y when x = 5.
Varying inversely would mean you use the equation \[y = \frac{ k }{ x }\] first...we want to solve for 'k' to use later....so you have y = -6 x = -2 plug those into that equation and solve for 'k'...what do you get?
-2=k/-6
Well you actually switched the 'x' and 'y' it should be -6 = k/-2 but close.. so now..solve for 'k' by multiplying both sides of the equation by -2..what does 'k' equal?
k=12 ?
right....that is what we get for 'k' Now...we have a second part of the question...solving for y when x = 5 to do this we use that same equation \[y = \frac{ k }{ x }\] you now know....k = 12 and x = 5 so plug those in..and solve for y...
what is 12/5 ?
12 / 5 equates to 2.4 so y = 2.4 when x = 5
thanks! can you help with this: Assume that y varies inversely with x. If y = 8.8 when x = 2.4, find x when y = 2.1. Round to the nearest tenth.
This would be the same thing... use the equation \[y = \frac{ k }{ x }\] input your 'y' and 'x' to solve for 'k' first....then use that 'k' and your given 'y' value to solve for 'x'
ok thanks for the equation. that will help tons! :D
No problem... Remember that varying inversely \[y = \frac{ k }{ x }\] if it says it varies directly you would use \[y = k x\] hope that helps!
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