Question

what are the foci of (x-3)^2/169+(y+5)^2/144=1
(–8, 5) and (2, 5)

Answer 1

unfortunately this is incorrect

Answer 2

ok can you tell me how to do this ?

Answer 3

the major axis is the longer axis

Answer 4

sqrt(169) = 13
sqrt(144) = 12

so 13*2 = 26 is the length of the major axis and it is horizontal since it's under the x^2 term

Answer 5

the center of this ellipse is what point?

Answer 6

-5,3 ?

Answer 7

no

Answer 8

Hint: the center of (x-h)^2/a^2+(y-k)^2/b^2=1 is (h,k)

Answer 9

so is it -3,5 ?
what are the foci of (x{{{-3}}})^2/169+(y{{{+5}}})^2/144=1

Answer 10

closer, but you have your signs mixed up

Answer 11

the center is actually (3,-5)

Answer 12

so (h,k) = (3,-5)

Answer 13

now we need to find the focal distance c

c^2 = a^2 - b^2

c^2 = 13^2 - 12^2

c^2 = 169 - 144

c^2 = 25

c = sqrt(25)

c = 5

This is the distance from the center to either focus (and you go along the major axis)

Answer 14

So one focus is at (h-c, k)

Another focus is at (h+c, k)

Answer 15

h = 3
k = -5
c = 5

Answer 16

so plug it in ? (3-5, -5)

Answer 17

yes, so that gives you (-2, -5)

Answer 18

do the same for (h+c, k)

Answer 19

(3+5, -5)
(8,-5)

Answer 20

good, your two foci are: (-2,-5) and (8,-5)

Answer 21

omg thankyouu (:. ive been asking for help all day. and no one was helping . i greatly appreciate it. (:. i have more okk ?

Answer 22

how much more?

Answer 23

and i'm sry no one else would help

Answer 24

like 6. you can just tell me if its right or wrong if you want.

Answer 25

alright that sounds like a plan

Answer 26

what you get wrong, try to work them again and come back

Answer 27

okk. want me to just put them here ?

Answer 28

either way works

Answer 29

1)What is the focus of the parabola y = -1/16(x+3)²-6
(–3, –10)
2)given the ellipse ((x - 4)^2)/169 + ((y + 8)^2)/100 = 1 and the hyperbola ((x - 4))^2)/169 + ((y + 8)^2)/100 = 1, which has a greater value?
hyperbola
3)What is the transverse axis and conjugate axis of the hyperbola y²/81-x²/121=1
The transverse axis is 121 and the conjugate axis is 81.

Answer 30

1)What is the focus of the parabola y = -1/16(x+3)²-6

(–3, –10)

correct

Answer 31

#2 doesn't make much sense...what two values are you comparing exactly?

Answer 32

im not sure what the question was asking , i just guessed.
ellipse

hyperbola

neither

cannot be determine

Answer 33

those were the options,

Answer 34

is that the full question for #2?

Answer 35

yess.

Answer 36

hmm not sure what to make of #2 then

#3 is incorrect

Answer 37

okk . ill try and figure it out again. thankyou (:

Answer 38

yw