Question

Please help:
Find all solutions to the equation.

sin^2(x) + sin (x) = 0

Answer 1

ok u know that\[\sin 2x=2 \sin x\cos x\]so equation becomes\[2 \sin x\cos x+\sin x=0\]take out common factor\[\sin x(2\cos x+1)=0\]using zero product property\[\sin x=0\]or\[2\cos x+1=0\]

Answer 2

but the equation is sin^2(x)

Answer 3

oh sorry\[\sin^2 x+\sin x=0\]take out common factor\[\sin x(\sin x+1)=0\]easier :)

Answer 4

\[\sin x=0\]or\[\sin x=-1\]

Answer 5

makes sense?

Answer 6

a little but i dont know how to get the solutions

Answer 7

u start like this: Let x be sin(x)
and x^2+x=0
x(x+1)=0
then, x=0; & x=-1
sin is at radian -3/4pi and pi

Answer 8

u substitute x value in sin(x)
and -1 is co-terminal (270) angle and 0