the square of x is = to 4 times the square of y. If x is 1 more than twice y , what is the value of x?
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OpenStudy (anonymous):
(2y + 1)^2 = 4y^2
OpenStudy (anonymous):
2y + 1 = 4y^2
OpenStudy (anonymous):
2y + 1 = 4y*
OpenStudy (blueraverwolf):
X=1/2
OpenStudy (anonymous):
can i do that
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OpenStudy (anonymous):
report raver plz tired of trolls
OpenStudy (blueraverwolf):
what are you talking about
OpenStudy (anonymous):
x = 4y^2
x = 2y +1
4y^2 = 2y +1
4y^2 - 2y -1 = 0
quadratic equation to solve for y
OpenStudy (anonymous):
u cant help by giving out answers ,... kid just get out .. obv common sense . OBV TROLL OBV
OpenStudy (anonymous):
whats wrong with my way?
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OpenStudy (anonymous):
you read the question wrong
it says that x = 2y +1
not x = (2y+1)^2
OpenStudy (anonymous):
was plugign it in the original equation
OpenStudy (anonymous):
x^2 = 4*y^2
OpenStudy (anonymous):
then subsitutting x
OpenStudy (anonymous):
with y
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OpenStudy (anonymous):
ohh is says the square of x at the beginning, okay i didn't see that
makes it much easier
OpenStudy (anonymous):
2y +1 = 4y
1 = 2y
y = 1/2
plug that in for x = 2(1/2) +1
x = 2
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
the thing is thats not a answer
OpenStudy (anonymous):
the answer is 1/2 but i still don't get how anyone can get that
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OpenStudy (anonymous):
sorry 1/4
OpenStudy (anonymous):
@Preetha
OpenStudy (anonymous):
x^2 = 4*y^2
x = 1 + 2y
Substitute the second equation in the first
(1+2y)^2 = 4y^2
1 + 4y + 4y^2 = 4y^2
4y = -1
y = -1/4
Substitute in y = -1/4 into the second equation:
x = 1 - 2/4
x = 1/2