Question

5/4x^2y- y/14xz

Answer 1

is this
\[\frac{5}{4x^2y}-\frac{y}{14xz}\]?

Answer 2

Yes!:)

Answer 3

ok so you have to subtract, and before you can do that you need to write both of them over a common denominator

Answer 4

the least common multiple of \(4x^2y\) and \(14xz\) is \(28x^2yz\)

Answer 5

\[\frac{5}{4x^2y}\times \frac{7z}{7z}=\frac{35z}{28x^2yz}\]
\[\frac{y}{14xz}\times \frac{2xy}{2xy}=\frac{2xy^2}{28x^2yz}\]

Answer 6

now you can subtract them, since they have the same denominator, and you get
\[\frac{35z}{28x^2yz}-\frac{2xy^2}{28x^2yz}=\frac{35z-2xy^2}{28x^2yz}\]

Answer 7

Okay, that's what I got to. But you just leave it like that or simplify it?

Answer 8

there is nothing to "simplify" here
there are no common factors top and bottom to cancel for example
this is the best you can do

Answer 9

Thank yo!!

Answer 10

yw