Find the vertex and parabola by writing in vertex form.
F(x)=x^2-2x-10

Question

Find the vertex and parabola by writing in vertex form. 
F(x)=x^2-2x-10

anonymous · Answer

Thank you !

anonymous · Answer

derivative?

anonymous · Answer

first coordinate of the vertex is $-\frac{b}{2a}$ which in your case is $-\frac{-2}{2}=1$

anonymous · Answer

second coordinate of the vertex is what you get when you replace $x$ by $1$

anonymous · Answer

to write it in "vertex form" put 
$$x^2-2x-10=(x-1)^2+k$$ where $k$ is the second coordinate of the vertex found above

anonymous · Answer

like heck
using calculus to find the vertex of a quadratic is like using a shotgun on a fly
plus, my guess is whoever asked the question isn't in calculus, because it asks for "vertex form"

anonymous · Answer

in any case if you take the derivative of $ax^2+bx+c$ you get $2ax+b$ which, if you set equal to zero and solve, gives $x=-\frac{b}{2a}$
it never changes, so you might as well just go with $-\frac{b}{2a}$

tkhunny · Answer

@Loser66 No.  Some people are just polite and always say "Thank you".  There is no natural pathway from the derivative to the vertex form.  This is very clearly NOT a calculus question.  The vertex form is a clear predecessor to any calculus application.

loser66 · Answer

@tkhunny , I just give out the way to find vertex, I didn't indicate about the form. Yes, My fault. I apologied.

tkhunny · Answer

No worries.  Always grateful for those willing to help.