Factor out the Monomial

1/(2x^2+4x)=
1/x(

Question

Factor out the Monomial

1/(2x^2+4x)=
1/x(

jhannybean · Answer

For this one you have 
$$\large \frac{1}{2x^2+4x}$$

There is a common multiplier at the bottom,can you tell me what it is?

jhannybean · Answer

hint: it's2 terms,and one of them is a multiple of 2.

anonymous · Answer

Well I see 1/2x being taken out.

jhannybean · Answer

Good! not "taken out" per say,but "factored out"
$$\large \frac{1}{2x(x+2)}$$

anonymous · Answer

The problem only asks to take out (1/x).
I'm thinking that I write it like

1/x(1/(2x+4)

Does that look correct?

jhannybean · Answer

Well,if you took out only 1 x from the denominator...you would have..
$$\large \frac{1}{x(2x+2)}$$

jhannybean · Answer

ack,sorry. 4 instead of 2.

anonymous · Answer

Alright I think that answers my question thanks :)

jhannybean · Answer

$$\large \frac{1}{x(2x+4)}$$

jhannybean · Answer

Which is kind of incorrect because when you're "taking out" or"factoring" a function, you look for common multipliers that appear in all terms, and take out the LCM. that includes numbers and variables.

jhannybean · Answer

Between 2 and 4, 2 is the LCM, and between x and x^(2), x is the LCM.