Question

Solve the inequality. Graph the solution.

2l x+1/3 l <9

Answer 1

start with
\[|x+\frac{1}{3}|<\frac{9}{2}\]

Answer 2

then make a sandwich
\[-\frac{9}{2}<x+\frac{1}{3}<\frac{9}{2}\]
solve by subtracting \(\frac{1}{3}\) all the way across

Answer 3

you got this?

Answer 4

ok im lost.

Answer 5

ok lets go slow

Answer 6

is this the original question
\[2|x+\frac{1}{3}|<9\]?

Answer 7

yes. A. -4 5/6 < x< 4 1/6
B. -4 1/3 < x < 4 1/3
C. -4 1/3 or x > 4 1/3
D. -4 5/6 or x > 4 1/6

Answer 8

ok so one thing we can do is ignore the last two answers, because if you have an absolute value LESS THAN something , you are going to get an inequality that looks like this
\[a<x<b\]

Answer 9

when u said frac(1)(3) u mean 1/3 right?

Answer 10

B was wrong

Answer 11

oooh if you cannot read what i wrote
refresh your browser

Answer 12

so it is A?

Answer 13

it is not reading the latex for some reason
try refreshing and you should see it

Answer 14

well, if it is not B it must be A because it is not C or D for sure

Answer 15

can you read what i wrote above?

Answer 16

i'll write it without the latex
-9/2 < x+1/3 < 9/2
-9/2-1/3<x<9/2-1/3

Answer 17

omg yes. I should've refresh it. but thank you so much!

Answer 18

yw
it is A, hope the method is clear

Answer 19

why ru so good at math? r u a teacher?

Answer 20

btw it is good to know when you start what the answer will look like
if it is
\[|something |<p\] it will be
\[a<x<b\] but if it is \(|something |>p\) it will be \(x<a\) OR \(x>b\)

Answer 21

lol, i am a car

Answer 22

Okay :)