Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

How much work will a machine with a power rating of 1.1..*.10³ watts do in 2.0 hours?

OpenStudy (unklerhaukus):

For constant power Work equals power times time \[W=PT\]

OpenStudy (unklerhaukus):

\[\quad=1.1\times10^3[\text W]\times2.0[\text h]\\ \quad=(1.1\times2.0\times10^3)[\text W\cdot\text h]\]

OpenStudy (unklerhaukus):

maybe your final answer is best in units of kilowatthours [kWh]

OpenStudy (anonymous):

the answers are 1.5*10^6 jolues 2.1*10^6 jolues 4.0*10^6 jolues 8.1*10^6 jolues

OpenStudy (unklerhaukus):

oh you have to convert to joules

OpenStudy (unklerhaukus):

A watt is a joule second \[[\text W]=[\text J\cdot \text s]\] An hour is \[[\text h]=60[\text{min}]=3600[\text s]\]

OpenStudy (anonymous):

i found the answer thanks tho:) how about this one? The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the inclined plane?

OpenStudy (unklerhaukus):

Im not getting any of your options was the power ment to be 1.125 x 10^3 [W] ?

OpenStudy (anonymous):

it was -2.1*120^6

OpenStudy (unklerhaukus):

i dont know how you can get a negative number

OpenStudy (anonymous):

i didnt get the answer i guessed it and i got it wrong,

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!