How much work will a machine with a power rating of 1.1..*.10³ watts do in 2.0 hours?
For constant power Work equals power times time \[W=PT\]
\[\quad=1.1\times10^3[\text W]\times2.0[\text h]\\ \quad=(1.1\times2.0\times10^3)[\text W\cdot\text h]\]
maybe your final answer is best in units of kilowatthours [kWh]
the answers are 1.5*10^6 jolues 2.1*10^6 jolues 4.0*10^6 jolues 8.1*10^6 jolues
oh you have to convert to joules
A watt is a joule second \[[\text W]=[\text J\cdot \text s]\] An hour is \[[\text h]=60[\text{min}]=3600[\text s]\]
i found the answer thanks tho:) how about this one? The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the inclined plane?
Im not getting any of your options was the power ment to be 1.125 x 10^3 [W] ?
it was -2.1*120^6
i dont know how you can get a negative number
i didnt get the answer i guessed it and i got it wrong,
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