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Mathematics 15 Online
OpenStudy (anonymous):

In the figure, ABCD is a rectangle. If the area of triangle AEB is 12, what is the area of triangle ACD?

OpenStudy (anonymous):

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OpenStudy (anonymous):

@sakigirl are u attempting any of these urself?

OpenStudy (primeralph):

Was wondering the same.

OpenStudy (anonymous):

@genius12 Yep! These are the ones that I do not understand. I have SAT homework, and I'm posting the ones that I didn't get.

OpenStudy (anonymous):

AB=DC

OpenStudy (anonymous):

try to figure out of the ratio of the heights of AEB and ACD

OpenStudy (primeralph):

.............you can just use ratios.......

OpenStudy (anonymous):

Call the length 'x' and width 'y'. Then the area of AEB is given by:\[\bf Area \ of \ \triangle AEB=\frac{ xy }{ 4 }\]Now the area of the triangle BEC would be given by:\[\bf Area \ of \ \triangle BEC =\frac{ xy }{ 4 }\]As you can see they're equal.

OpenStudy (anonymous):

@primeralph ok smart guy thats cool

OpenStudy (dan815):

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