Question

Post your Edx 6.002 Final Exam 2013 questions and I'll provide you the answer.

Answer 1

Q1,2,3,4,5 all

Answer 2

Q3 F,W,C,Y.D.X ?

Answer 3

wt about others..cn u let me know the formula at least

Answer 4

don't post just question numbers because questions are different for every person. Post the complete screenshot of your question then only i can help.

Answer 5

and also don't message me. If you want answers then post it here.

Answer 6

q4

Answer 7

q4

Answer 8

post one more screenshot kamash. what's below the screenshot untitiled2.png?

Answer 9

Okay, i'll solve this question and post it here with complete solution. :)

Answer 10

Hello, Please try this too! @halfwebprince

Answer 11

Help me out in Q1

Answer 12

anyone suggest me to how to solve q1? problem

Answer 13

R = Ron(Vs/Vout - 1)

Answer 14

@Tcher vout value not given in question

Answer 15

V is Vout

Answer 16

YES)))

Answer 17

Tcher, if you copy somebody's equation from chat then please give him the credit. okay?

Answer 18

wat value should i put for V from these??
Vil=2.5, Vol=1.5V, ViH=7.5v, Voh=8.5

Answer 19

OK? it is from final review - S2012))

Answer 20

@Halfwebprince wat value should i put for V from these?? Vil=2.5, Vol=1.5V, ViH=7.5v, Voh=8.5

Answer 21

you have to provide Ron value

Answer 22

Ron=200

Answer 23

Vs=10

Answer 24

okay, then 200(10/1.5 - 1)

Answer 25

i don't have calculator right now because i am not home. so you have to calculate that equation by yourself. I don't have even paper and pen to calculate it for you.

Answer 26

Yeah I have calculated Thanks :).. what about rest of parts of Q1??

Answer 27

could you post the rest part. It's different for different person

Answer 28

@halfwebprince wht abt q4

Answer 29

kamash, sorry I'll calculate for it. After my lunch i'll surely solve it and post it here. sorry for the delay.

Answer 30

okay, i am going for my lunch. after that i'll solve for both of your questions. Also if you have any answer then share it along with the method to help other students.

Answer 31

thnx in advance

Answer 32

@abdullatif92211 do u hv answrs to othr ques?

Answer 33

rest of part of Q1

Answer 34

@kamash trying to solve :)

Answer 35

Q5 need help!

Answer 36

@Tcher have u solved Q1??

Answer 37

only part1 320 om

Answer 38

@Tcher i have also solved that part only.. and wat about Q2??

Answer 39

2mA

Answer 40

q2 p1 id=2mA

Answer 41

what formula should v apply coz parameters are different

Answer 42

and wat about rest of 3 parts of Q2?? @fazal7

Answer 43

WILL GIVE U AFTER PRAYER ITS TIME FOR PRAYER

Answer 44

@fazal7 ok fazal waiting for u :)

Answer 45

head stopped to think)))) a lot of work, and we have yet to solve this exam)

Answer 46

cn u help with q4

Answer 47

Which of the diagrams above represents the small signal equivalent circuit for the amplifier with the capacitive and resistive load? q2?

Answer 48

Q1

In this problem, we look at the design of an inverter. For the entirety of this problem VS=7.0V, and all transistors are modeled with the SR model with RON=120Ω. We design the inverter shown in Figure 1.


Figure 1
The static discipine of the inverter is VIL=2V, VOL=1V, VIH=5V, and VOH=6V. What is the minimum resistance (in Ohms) that R can be to meet this static discipline?

unanswered

We now cascade two of these inverters shown in Figure 2. Assume that R=3kΩ. We want to ananlyze the speed of our inverter, so we model the parasitic capacitance at node B as the gate-to-source capacitance of the the second gate, CGS=0.3pF.


Figure 2
First we consider the case where the voltage at node B is rising. What is the time (in nanoseconds) after the falling edge at node A, that it takes for the signal at node B to rise from 0V to VOH=6V?
unanswered

Now we consider the case where the voltage at node B is falling. After the rising edge at node A, what is the Thevenin equivalent resistance (in Ohms) as seen by the gate-to-source capacitance, CGS?

unanswered
What is the time constant, τf (in picoseconds), for this falling transient voltage?
unanswered
What is the time (in picoseconds) that it takes for the signal at node B to fall from 7.0V to the value of VOL=1V?

Answer 49

hello friend

Answer 50

Q4

In this problem we investigate the time response of the circuit shown in Figure 4 which contains one switch. We are given that \(V_0=40 V\), \(R_1=100 \Omega\), \(R_2=100 \Omega\), \(R_3=200\Omega\), \(L=1H\), and \(C=100 \mu F\)
Figure 5

Until time \(t=0\), the switch is open and the circuit is initially at steady-state. For \( t < 0 \) what is the voltage across the capacitor, \(v_C(t < 0)\), and the current through the inductor, \(i_L(t < 0)\)?

\(v_C(t < 0)\) (in Volts)

unanswered

\(i_L(t < 0)\) (in milliamps)

unanswered

At \(t=0\), the switch is closed and after a LONG LONG time reaches steady-state again. What is the voltage across the capacitor and the current through the inductor after the switch is closed for a LONG LONG time?

\(v_C(t >> 0)\) (in Volts)

unanswered

\(i_L(t >> 0)\) (in milliamps)

unanswered

For \(t>0\), we can write a second order differential equation for the current through the inductor of the form:
[mathjax] V_0 = X \frac{d^2i_L(t)}{dt^2} + Y \frac{di_L(t)}{dt} + Z i_L(t) [/mathjax]

Write your answers for \(X\), \(Y\) and \(Z\) below in terms of \(R_1\), \(R_2\), \(R_3\), \(C\), and \(L\).

\(X\)

unanswered

`{::}`

\(Y\)

unanswered

`{::}`

\(Z\)

unanswered

`{::}`

Answer 51

In this problem we investigate the time response of the circuit shown in Figure 4 which contains one switch. We are given that V0=20V, R1=50Ω, R2=50Ω, R3=300Ω, L=1.5H, and C=200μF
Figure 5

Until time t=0, the switch is open and the circuit is initially at steady-state. For t<0 what is the voltage across the capacitor, vC(t<0), and the current through the inductor, iL(t<0)?

vC(t<0) (in Volts)

unanswered

iL(t<0) (in milliamps)

unanswered

At t=0, the switch is closed and after a LONG LONG time reaches steady-state again. What is the voltage across the capacitor and the current through the inductor after the switch is closed for a LONG LONG time?

vC(t>>0) (in Volts)

unanswered

iL(t>>0) (in milliamps)

unanswered

For t>0, we can write a second order differential equation for the current through the inductor of the form:
[mathjax] V_0 = X \frac{d^2i_L(t)}{dt^2} + Y \frac{di_L(t)}{dt} + Z i_L(t) [/mathjax]

Write your answers for X, Y and Z below in terms of R1, R2, R3, C, and L.

X

unanswered

{::}

Y

unanswered

{::}

Z

unanswered

{::}

Answer 52

plz say answers for Q4 & Q5...... just 2 hours left.....

Answer 53

Can u help me with Q2.. Help me with the equations to solve:-

The question starts with:- In the circuit below, we ignore all parastic capacitances and there is only one capacitor labeled C and has a capacitance of 14pF..
Need 5% to earn a certificate....

Answer 54

@tcher i am solved Q4 and Q5 completely except for that X Y Z in Q4. Tell me your parameters and I'll give you the answer. The process is long so i can't write it down here. It involves differential equation.

Answer 55

@guduma here is your Q3 answers : FWCYDX

Answer 56

@JULIAKAPRI okay, just wait for some minutes so that i can solve for it.

Answer 57

so many people are messaging me. I can't solve all of them together. one by one please.

Answer 58

have litle patience guys. i'l give answers to all of you. don't worry.

Answer 59

In this problem we investigate the time response of the circuit shown in Figure 5 which contains one switch. We are given that V0=40V, R1=100Ω, R2=100Ω, R3=200Ω, L=1H, and C=100μF Until time t=0, the switch is open and the circuit is initially at steady-state. For t<0 what is the voltage across the capacitor, vC(t<0), and the current through the inductor, iL(t<0)?vC(t<0) (in Volts)At t=0, the switch is closed and after a LONG LONG time reaches steady-state again. What is the voltage across the capacitor and the current through the inductor after the switch is closed for a LONG LONG time?vC(t>>0) (in Volts)iL(t>>0) (in milliamps)For t>0, we can write a second order differential equation for the current through the inductor of the form:
V0=Xd2iL(t)dt2+YdiL(t)dt+ZiL(t)
Write your answers for X, Y and Z below in terms of R1, R2, R3, C, and L.

Answer 60

Good day!)

Answer 61

hi Tcher, i am solving for @JULIAKAPRI and i 'm almost done. next i'll solve for you.

Answer 62

done guys.

Answer 63

now i am posting everybody's answer one of one.

Answer 64

@Tcher Q5(a) = 0

Answer 65

@JULIAKAPRI same for you

Answer 66

If Q5 is not solved

Answer 67

OK

Answer 68

Q5 is solved. i'm posting the answer one by one after putting your parameter values in matlab.l

Answer 69

Thanks)))

Answer 70

ok tell me ans for Q5

Answer 71

tell me q5 answers

Answer 72

@halfwebprince can u tell me how u are solving in MATLAB????
can u tell me the procedure

Answer 73

@Tcher what's the value of t in your Q5

Answer 74

for first and second part.

Answer 75

200ms

Answer 76

spandu, i am asing tcher because i promised him yesterday that i'll give him answer. Then'll solve for you.

Answer 77

could you type answers for JULIAKAPRI here I have the same Q5

Answer 78

plz Help me also......

Answer 79

200 ms

Answer 80

@aparnasharma yes i help you also. don't worry. I'll solve for everybody's question. it's quite fun and i'm on leave so i don't have much work to do.

Answer 81

@halfwebprince do u have answers for Q4? please help me

Answer 82

@tcher, for both inductor (first part) and capacitor (seoncd part?)

Answer 83

ya same for t value

Answer 84

yes 200

Answer 85

@kashu,
I have but i don't have X Y and Z expression. for rest of the question of Q4 i have answers.