Question

At a temparature of 20 degree C the common amoeba reproduces by splitting in half every 24 hours.if we start with a single amoeba how many will there be after a)8 days b)16 days?

Answer 1

where are you finding the problem to solve it..??
i'll try to correct you..:)

Answer 2

well i am giving SAT and from D.Rayners book :)@RaGhavv

Answer 3

no no...tell me where are you stuck up??...i mean how you solved it...or not able to..i will correct you..!

Answer 4

WELL i don't know :/

Answer 5

y(t) = a × e^kt

Where:
y(t) = value at time "t"
a = value at the start
k = rate of growth (when >0) or decay (when <0)
t = time

Answer 6

this is an exponential growth rate question, can you work it out from the above formula...?

Answer 7

i will try

Answer 8

see..its quite easy..you actually can solve it by your logic,,,,not many equations are required to solve this...so you must first try...

Answer 9

y(t) = a × e^kt
a = 1 amoeba

population doubles every day, so after 1 day... population =2

y(t) = a × e^kt
2 = 1 x e^kt ... 1 day so t = 1
2 = 1 x e^1k
2 = e^k
k = log 2

so now you have all the constants

so when t = 8days
y(t) = a × e^kt
y = 1 × e^(log2)t
y = 1 × e^(log2)×8
y = e^5.55(...ish)
y = 256
so population after 8 days = 256

Answer 10

i.e 2^8

Answer 11

@zzr0ck3r totally, but that only works if the rate is a simple number... ie doubles every 3 hrs...

Answer 12

you said yourself it doubles every day:)
\[2^{number-of-days}\]

Answer 13

correct