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Mathematics 7 Online
OpenStudy (anonymous):

Find the differential of this function. y=tan(sqrt(t))

OpenStudy (cwrw238):

your function doesn't make sense i think it shod be y=tan (sqrt(t))

OpenStudy (anonymous):

sorry that's what I meant

OpenStudy (cwrw238):

note that this function can be described as ' a function of a function' - sqrt(t) is a function of t and tan (sqrt(t)) is a function of sqrt (t) and its differentiated by the chain rule

OpenStudy (cwrw238):

(f(g(t))' = f'(g(t)) * g'(t) g'(t) = (1/2)t^(-1/2) f'(g(t)) = sec^2 (t^(1/2))) (note sqrt t = t^(1/2))

OpenStudy (cwrw238):

now you need to simplify g'(t) * f' (g(t))

OpenStudy (cwrw238):

need any more help ?

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