Five friends agree to save money for a graduation road trip. They decide that each of them will put $0.25 in the fund on the first day of May, $0.50 on the second day, $0.75 on the third day, and so on. At the end of May, there will be $_____ in their fund. (Hint: There are 31 days in May.)
$0.25 + $0.50 + $0.75 + ... What type of sequence is this, arithmetice or geometric?
um i think arithmetice
Correct, since there is always a fixed difference (called "common difference") between any two consecutive terms
You know the first term of the series is 0.25. The common difference is 0.25. You need to find the sum up to term number 31.
The sum is Sn = n(a1 + an)/2 where n is the number of the last term. In this case, n = 31. a1 is the first term, which in this case is 0.25. a31 is the 31st term. The formula for an is: an = a1 + (n -1)d
After you find the sum, multiply it by 3 since there are three people contributing to the fund.
Are you following this?
23.25???
How did you get that?
You need three steps: 1. Find a31, the 31st term of the series 2. Find S31, the sum of the series up to and including the 31st term 3. Multiply S31 by 3 What did you get for a31?
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