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Mathematics 20 Online
OpenStudy (anonymous):

Five friends agree to save money for a graduation road trip. They decide that each of them will put $0.25 in the fund on the first day of May, $0.50 on the second day, $0.75 on the third day, and so on. At the end of May, there will be $_____ in their fund. (Hint: There are 31 days in May.)

OpenStudy (mathstudent55):

$0.25 + $0.50 + $0.75 + ... What type of sequence is this, arithmetice or geometric?

OpenStudy (anonymous):

um i think arithmetice

OpenStudy (mathstudent55):

Correct, since there is always a fixed difference (called "common difference") between any two consecutive terms

OpenStudy (mathstudent55):

You know the first term of the series is 0.25. The common difference is 0.25. You need to find the sum up to term number 31.

OpenStudy (mathstudent55):

The sum is Sn = n(a1 + an)/2 where n is the number of the last term. In this case, n = 31. a1 is the first term, which in this case is 0.25. a31 is the 31st term. The formula for an is: an = a1 + (n -1)d

OpenStudy (mathstudent55):

After you find the sum, multiply it by 3 since there are three people contributing to the fund.

OpenStudy (mathstudent55):

Are you following this?

OpenStudy (anonymous):

23.25???

OpenStudy (mathstudent55):

How did you get that?

OpenStudy (mathstudent55):

You need three steps: 1. Find a31, the 31st term of the series 2. Find S31, the sum of the series up to and including the 31st term 3. Multiply S31 by 3 What did you get for a31?

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