a skaterboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. how much higher is he when he comes to a stop? (energy problem)
this is basic energy problem. equate kinetic energy to potential energy. \[v ^{2}/2\] =\[g*h\] solving you get h =1.4048m
thank you so much!!!!!
@jenniem29 happy that it helped :)
can you help me again?
my pleasure...
thank u
a diver is on a board 1.80m above the water. she jumps straight up at 3.62 m/s. what is her maximum height above the water?
this is similar to the previous one, the only differenc is that you have to add 1.80 to the final answer. then final answer will be 1.8 + \[3.62^{2}\div(2*9.81)\] = 2.46
is right!! thank soooo much!!!!! :)
one more question. how do i solve of the velocity?
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