Question

The slope of the tangent to the curve y=x^2 - x at the point where the line y=2 cuts the curve in the first quadrant is?

Answer 1

dy/dx=2x-1
2=x^2-x
gives x=2 and x=-1
dy/dx=3 and -3
I'm getting 2 options..but the answer is either of them,how do i decide?

Answer 2

dy'dx = 3 is in first quadrant

Answer 3

why cant it be -3?

Answer 4

the point (2,2) is in the first quadrant (the point where y = 2 cuts the curve)
the slope at this point is 2(2) - 1 = 3

Answer 5

oh,didn't realise this small thing.
Thanks!

Answer 6

yw