Question

Please Help!!!

Answer 1

.....can't really see the lettering........

Answer 2

@amistre64 can you help with this?

Answer 3

Isn't a confidence level of 90%, 2 std deviations?

Answer 4

no

Answer 5

I was thinking 95.5%, the C.I. was how you found your column on the 't' or 'z' table.

Answer 6

what? where did you get 95.5% from?

Answer 7

The formula needed is
\[(\bar {x _{1}}-\bar {x _{2}})-1.645\sqrt{\frac{\sigma _{1}^{2}}{n _{1}}+\frac{\sigma _{2}^{2}}{n _{2}}}<\mu _{1}-\mu _{2}<\ ...............\]
The expression to the right of the difference in the means is the same as the expression to the left except there is an addition sign before 1.645.