Question

a stone is dropped from a height of 7.70m. how fast is it going when it reaches the ground?

Answer 1

h = 7.70 m

acceleration due to gravity = g = 9.8 m/s^2

formula for position with initial velocity of 0 and constant acceleration is \[x(t) = \frac{1}{2}at^2\]\[a=g\]We can solve for x(t) = 7.70 and find the value of \(t\). Knowing \(t\) we can use \(v = at = gt\) to find the velocity when it hits the ground.

Answer 2

i got the answer for this question already :)

Answer 3

okay, well, it was the one I had time for :-)

Answer 4

okay thank u

Answer 5

I'll have a look at your open problems later and see if I can offer any more suggestions.