Question

Factor completely: ax + 2ay + bx + 2by
@ash2326

Answer 1

We have
\[ax+2ay+bx+2by\]
Let's take out a from the first two terms, we get
\[a(x+2y)+bx+2by\]
@unheard can you take out anything common from the last two terms?

Answer 2

b is common.

Answer 3

Can you take it out?

Answer 4

I forgot how .-.

Answer 5

\[ b\times x +2\times b \times y\]
b is multiplied to both the terms.
Let's divide both terms by b
we get
\[(x+2y)\]
do you understand it ?

Answer 6

Just.. take em out? .-. Sorry. I'm not good at this at all. > . <

Answer 7

no problem, we'll learn it.

Answer 8

ok, for example we have
\[x+2xy\]
can you try?

Answer 9

divide both sides by x?

Answer 10

yes, divide by x and bring it out

Answer 11

2y?

Answer 12

Ok, I'll show how to divide
\[\frac{x}{x}+\frac{2xy}{x}\]
\[\frac{1 \cancel x}{\cancel x}+\frac{2y \cancel x}{\cancel x}\]
We get 1+2y

Answer 13

Oh, I thought it'd be 1 but I wasn't sure.

Answer 14

no problem.
So we get
\[x(1+2y)\]

Do you get it?

Answer 15

Yes, I get it now.

Answer 16

@ash2326

Answer 17

@radar

Answer 18

sorry i was away

Answer 19

Are you here?

Answer 20

@radar helped me with the rest. But thanks!

Answer 21

Cool, let me know if you need help with anything else.