Question

What's the simplified form of y^2+7y+12/y^2-2y-15

Answer 1

Factorize both the quadratic equations first and then divide them.
Can you do it ?

Answer 2

Do what?

Answer 3

Factorize the equations.

Answer 4

\[\large \frac{y^{2}+7y+12}{y^{2}-2y-15}\]factor out both the numerator and denominator.
numerator : what two numbers add to give 7 and multiply to give 12?
denominator: what to numbers add to give -2 and multiply to give -15?

Answer 5

numerator: 3 and 4
denominator: 3 and -5

Answer 6

correct :) \[\large \frac{(x+3)(x+4)}{(x-5)(x+3)}\] Now is there any like terms we can cancel out?

Answer 7

x+3

Answer 8

good! \[\large \frac{\cancel{(x+3)}(x+4)}{(x-5)\cancel{(x+3)}}\]

Answer 9

What does that leave us with?

Answer 10

x+4/x-5

Answer 11

You got it :)

Answer 12

thanks!

Answer 13

Using the Discriminant method, you'll get numerator=(y+3)(y+4)
And denominator=(y-5)(y+3)
So the answer will be (y+4)/(y-5)

Answer 14

\[\large \frac{y^{2}+7y+12}{y^{2}-2y-15} =\large \frac{(x+3)(x+4)}{(x-5)(x+3)}=\large \frac{\cancel{(x+3)}(x+4)}{(x-5)\cancel{(x+3)}}= \frac{x+4}{x+3}\]

Answer 15

A little bit of correction to the above comment.
Ans= (y+4)/(y-5) :)
Y+3 just got cancelled out.

Answer 16

Somehow my y's magically changed to x's. lol

Answer 17

I wasn't pointing towards X or Y. You wrote an incorrect denominator in the answer. That's what I was talking about.

Answer 18

Oh that lol.-_- I see it