Question

What is the solution to the equation log4 x + log4 8 = 3 ?

x = one–half

x = 2

x = 8

x = 32

Answer 1

I'd like to know whether 4 is the base or just being multiplied ?

Answer 2

i think its the base

Answer 3

the base

Answer 4

Using the log property\[\log_{4}(8x) = 3 \]\[8x = 4^{3}\]\[x = \frac{ 64 }{ 8 } = 8\]

Answer 5

\[\log_{4}( x)+ \log_{4}(8)= \log_{4}(8x)=3, 4^{3}=(8x), 64=(8x), x=64/8=8\]