Question

a 77.0 kg woman slides down a 42.6 m long waterslide inclined at 42.3 degress. at the bottom she is moving 20.3 m/s . how much work did friction on the woman? 42.6 is not her starting height

Answer 1

Ok, so the equation is:\[EK _{f}=EP _{i}-W \rightarrow W=EP _{i}-EK _{f}=mgh-\frac{ 1 }{ 2 }mv ^{2}\h is just pythagoras theorem.

Answer 2

can you help me? A woman pulls a 7.87 kg suitcase, initially at rest, with a 29.2 N force along the handle at 62.7 degrees. Friction pulls back at 11.7 N, and the suitcase moves 8.44 m. What is the total work done?