Question

Evaluate the integral using integration by parts where possible.
(X+1)e^x dx from 0 to 1

Answer 1

\[\large \int_{0}^{1} (x+1)\cdot e^{x}dx\]

Answer 2

\[\large {u = (x+1)\\du=dx}\]\[\large {dv=e^xdx\\v=e^x}\]

Answer 3

Can you solve it from here?

Answer 4

\[\large e^{x}(x+1)]_{0}^{1} - \int_{0}^{1} e^{x}dx\]

Answer 5

\[\large xe^{x}+e^{x} - e^{x}]_{0}^{1}\]

Answer 6

Input your values in the fashion \[\large F(b)-F(a)\] and you'll be set! :)

Answer 7

ok Thank you!!

Answer 8

\[\large [(1)e^{(1)}+e^{1}-e^{1}]-[(0)e^{0}+e^{0}-e^{0}]\]

Answer 9

No problem :)