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Mathematics 15 Online
OpenStudy (anonymous):

Factor completely: x^2 − 3x − 10 @Compassionate (x + 5)(x − 2) (x − 10)(x + 1) (x − 5)(x + 2) (x + 10)(x − 1)

OpenStudy (anonymous):

(x - 5)(x + 2) will be the correct answer

OpenStudy (compassionate):

Hello, my name is Stephen and I'll be your tutor. The first step is factoring the x-squared term. This isn't so hard. (x )(x ) Now the second step is saying, "what are the multiples of -10 that add up to negative ." 5 * -2 = 10 But 5 - 2 =/= -3 So that's not it Hmm... I wonder what it could be, hun?

OpenStudy (anonymous):

That add up to negative what? > . <

OpenStudy (compassionate):

That add up to negative 3, hun. What are two multiples of -10 that add up to negative 3.

OpenStudy (anonymous):

Oh, It didn't show up, sorry. But two multiplies are 5 and -2.

OpenStudy (jhannybean):

Or you can think about it this way. Which two numbers ADD t give you -3 and MULTIPLY to give you -10?

OpenStudy (anonymous):

I can't think of any :/

OpenStudy (mathstudent55):

"what are the multiples of -10" You mean factors of -10, not multiples.

OpenStudy (mathstudent55):

@unheard Can you list all pairs of numbers that multiply to -10? I'll do the first two for you: -1, 10 -10, 1

OpenStudy (anonymous):

-2, 5 5, -2

OpenStudy (mathstudent55):

Great. Here are all 4 sets of pairs: -1, 10 -10, 1 -2, 5 5, -2 Now can you write, at the end of each line, the sum of the two numbers. I've done the first one for you (copy and paste the text below): -1, 10; sum 9 -10, 1; sum -2, 5; sum 5, -2; sum

OpenStudy (anonymous):

-10, 1; sum -9 -2, 5; sum 3 5, -2; sum 3

OpenStudy (mathstudent55):

Wait, notice your last two pairs are the same numbers. You should have -2, 5 -5, 2 Now do their sums.

OpenStudy (anonymous):

Ohh, the last one is -3

OpenStudy (mathstudent55):

Exactly. Since -5 and 2 multiply to -10 and add to -3, they are the factors of -10 you need. Now the factoring is simply putting those two numbers inside the parentheses, as @compassionate shopwed you above: x^2 − 3x − 10 = (x )(x ) Now place -5 and 2: (x - 5)(x + 2)

OpenStudy (anonymous):

Thanks!

OpenStudy (mathstudent55):

wlcm

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