a women pulls a 7.87 kg suitcase. initially at rest with a 29.2 N force along the handle at 62.7 degress. friction pulls back at 11.7 N and the suitcase moves 8.44 m what is the total work done?

Question

turingtest · Answer

$$\vec F=\vec F_{push}-\vec F_{friction}$$and work is$$\vec F\cdot \vec d=Fd\cos\theta$$

turingtest · Answer

where $\vec F$ is the total force

anonymous · Answer

cosine is 0?

turingtest · Answer

what is the angle $\theta$ between $\vec F$ and $\vec d$ ?

anonymous · Answer

147.7

turingtest · Answer

oh I'm sorry, I misunderstood the question

starting  over :p

what is the formula for friction force?

anonymous · Answer

mgh+1/2mv^2=mgh+1/2mv^2 thats the equations it give us

turingtest · Answer

sounds like you're looking up equations in your notes and books without really knowing what they mean

what you wrote there is conservation of energy for a falling object, and that obviously is not what we need right now.

What I said earlier is true: total forge times distance is work done. In order to know that you need to know the force of friction. Again, what is the formula for the force of friction?

turingtest · Answer

total force*

anonymous · Answer

it doesnt tell me

turingtest · Answer

are you sure that the problem is worded exactly correctly? is it being pulled 60 degrees up from the horizontal, or down, or side to side...?

turingtest · Answer

or is there a picture maybe? because the question is a bit incomplete

anonymous · Answer

no its just the question

turingtest · Answer

well I assume that they are pulling 62.7 deg up, in which case you need to find the normal force of the object against the ground, from which you can find the friction force. can you do that?