Find the exact real value of arccos(1/2)
have you tried it yet? it's just like the one we did
cos=adj/hyp
cos=1/2
but i cant figure out the rest. im trying to see how arccos changes that or changes my answer
actually sorry, this is just a special value
not the same as the last :P my bad
i thought so and plus the options dont match what i came up with.
like I said in the last post, what is the definition of the arccosine?
t=arccos(x) means what?
arccos(X)= cos(x)
no, the two functions are not the same... they are inverses
arccos(x)=t implies that cos(t)=x
so that means t is what kind of value?
oops. i dont know what t is, im confused.
t is for the triangle?
normally when we have \[\cos\theta=x\] what does \(\theta\) represent?
the theta is equal to the x or its just the value thats there
theta is *not* the x, x is the sine of theta theta normally represents an *angle*, right?
yes that makes more since
so if\[\sin\theta=x\]and\[\sin^{-1}x=\theta\]then inverse trig functions are like asking "at what angle theta is the sine of that angle x?"
so in your case the question becomes "the cosine of what angle(s) is/are 1/2 ?"
i see so we have the hyp and the opp sides and we need the angle
no, in this case this should be a value you have memorized the answer choices include pi unless they are in degrees, correct?
i think it is pi/6
so you are saying that cos(pi/6)=1/2 ?
the options are: pi/3 2pi/3 -pi/6 pi/6
no its pi/3
correct :)
thanks
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