Question

Please help me simplify the following radical. (click to see)

Answer 1

\[\sqrt{e ^{2x}+e ^{-2x}+2}\]

Answer 2

let \(e^{2x} = a\)

Answer 3

\[\sqrt{a+\frac{ 1 }{ a }+2}\]

Answer 4

\(\sqrt{a +\frac{1}{a}+2}\)

Answer 5

yes take lcd and group into a single fraction

Answer 6

\(\large \sqrt{\frac{a^2+1 + 2a}{a}}\)

Answer 7

see that, numerator is a perfect square

Answer 8

why isn't (1/a) multiplied by (a/a) as well?

Answer 9

i dont need to cuz, i already hav a in the bottom

Answer 10

oh right

Answer 11

good :) try to simplify now

Answer 12

i needed to simplify this radical in order to find the arc length of a parametric curve...im in calc iii and my algebra is pathetic.

Answer 13

its okay, see next steps :-

\(\large \sqrt{\frac{a^2+1 + 2a}{a}}\)

\(\large \sqrt{\frac{(a+1)^2}{a}}\)

Answer 14

ya i can go from here..thanks

Answer 15

\(\large \frac{(a+1)}{\sqrt{a}}\)

Answer 16

\(\large \frac{(e^{2x}+1)}{\sqrt{e^{2x}}}\)

Answer 17

\(\large \frac{(e^{2x}+1)}{e^{x}}\)

Answer 18

\(\large e^x - \frac{1}{e^{x}}\)

Answer 19

simplifies to this :)

Answer 20

why is the second term subtracted from the first here:
\[\large e^x - \frac{1}{e^{x}}\]

Answer 21

@ganeshie8

Answer 22

\(\large \frac{(e^{2x}+1)}{e^{x}}\)

Answer 23

\(\large \frac{e^{2x}}{e^{x}} + \frac{1}{e^{x}} \)

Answer 24

right so then it should be:
\[e ^{x}+\frac{ 1 }{ e^x }\]

right?

Answer 25

oops ! you're right !!!! i had a typo there sorry :/

Answer 26

no problem

Answer 27

thanks for the help

Answer 28

you're wlcme :) good luck wid calc :D