Indicate the equation of the given line in standard form.
The line with slope and containing the midpoint of the segment whose endpoints are (2, -3) and (-6, 5).
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OpenStudy (zale101):
For the midpoint, we have to us this formula ((x1+x2)/2,(y1+y2)/2)
OpenStudy (anonymous):
Was the slope given? It loks like you forgot to add it or no?
OpenStudy (anonymous):
-4,6
OpenStudy (anonymous):
Wait where did you get 9 from? zale101
OpenStudy (zale101):
oh i'm sorry lol
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OpenStudy (zale101):
So here we have ((2+(-6))/2,(-3+5)/2) =
OpenStudy (anonymous):
its ok i messed up too. it's 2, 3/2 or 7/2?
OpenStudy (zale101):
((2+(-6))/2= -2
(-3+5)/2= 1
OpenStudy (anonymous):
oh ok. what's next?
OpenStudy (zale101):
the slope is (change in y)/(change in x)
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OpenStudy (zale101):
or (y2-y1)/(x2-x1)
OpenStudy (zale101):
So (5+(-3))/(-6+2) = ?
OpenStudy (anonymous):
averages?
OpenStudy (zale101):
Do you know how to plug in the numbers into the formula's, like what i did here for example (5+(-3))/(-6+2) = ?
OpenStudy (zale101):
solve this for me (5+(-3))/(-6+2) = ?
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OpenStudy (anonymous):
sooo -3-5/2+6 = -8/8?
OpenStudy (zale101):
which equals -1
OpenStudy (anonymous):
so then after that i just do y-y1= -1(x1-x. which is y+3=-1(x-5)?
OpenStudy (zale101):
1 and -2 are the midpoints
OpenStudy (anonymous):
so (y-1)=-1(x=2)?
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