Question

x+2divided by7-x times x^2-9x+4divided by x^2-5x+6

Answer 1

can u factor x^2-5x+6 ?

Answer 2

\[\frac{ x+2 }{( 7-x )(x^2-9)}/x^2-5x+6\]

Answer 3

Is that the question?

Answer 4

no. the x+2 over 7-x times x^2-9x+4 over x^2-5x+6

Answer 5

1x+1 and 1x-6

Answer 6

i think its \(\large \frac{ x+2 }{( 7-x )}\frac{x^2-9x}{x^2-5x+6}\)

Answer 7

yes^

Answer 8

there is a +4 after -9x

Answer 9

x^2-5x+6 is not (x+1)(x-6), try again :)
ohh, so,
\(\large \frac{ x+2 }{( 7-x )}\frac{x^2-9x+4}{x^2-5x+6}\)

Answer 10

how is it not? 1*-6=-6 and 1*1=1 and those added together is -5?

Answer 11

instead of +4, is that by any chance, +14 ?

Answer 12

lol why yes

Answer 13

yes, but we need product as +6
now x^2-9x+14 can be factored ^_^

Answer 14

oh i thought i was looking for the middle, the -5

Answer 15

two numbers with product = +6 and sum = -5 ?

Answer 16

over my head lol

Answer 17

how about -2 and -3 ?

Answer 18

ok =]

Answer 19

x-2, x-3

Answer 20

top is -7, -2?

Answer 21

correct! so you can factor the quadratic equations :)
now try to factor, x^2-9x+14 :)

Answer 22

yes, -7, -2 are the 2 numbers, so factored form will be ?

Answer 23

(x-7)(x-2)

Answer 24

is that what your asking?

Answer 25

yes, correct
now plug these factored forms in to your original expression and see what gets cancelled !
note : 7-x = - (x-7)

Answer 26

is it (x+2)/(x+3)

Answer 27

the final answer ? no...
i think only x-7 is getting cancelled, everything else remains...

Answer 28

the x-2's dont cancle?

Answer 29

\(\large \frac{ x+2 }{-(x-7 )}\frac{(x-2)(x-7)}{(x-2)(x-3)}\)
and yes, x-2's also cancel

Answer 30

\(\large \frac{ (x+2) }{-\cancel{(x-7 )}}\frac{\cancel{(x-2)}\cancel{(x-7)}}{\cancel{(x-2)}(x-3)}\)
what remains ?

Answer 31

thank you!

Answer 32

finally we have -(x+2)/(x-3) or (x+2)/(3-x)
welcome ^_^