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10 points lie on the circumference of a circle. How many inscribed quadrilaterals can be drawn using these points as vertices? I'll give medals for sure:)
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Does anyone have an idea?
I not sure but I feel this is something involving factorials. You have 10 points and you choose different ways to connect four. Same as having ten chairs and 4 students. Then figuring out how many ways you can arrange the students in the ten chairs.
I like your approach!!!
yes, you need to choose 4 points to make a quadrilateral, out of 10 given points, so number of way(quadrilaterals) will be just 10 choose 4 .
yes, I'm not sure how to do 10C4
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\(\huge ^nC_r = \dfrac{n!}{r!(n-r)!}\) n=10, r=4
oh, wait a second
okay, that would be:
|dw:1371867073283:dw|
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