Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.
Standard form is Ax+By=C where A, B, and C are are integers (just plain positive or negative nuymbers without and fractions) Can you find slope?
is slop 1/3?
\[slope(m)=\frac{ y2-y1 }{ x2-x1 }\]
Correct
formula is\[y-y _{1}=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }(x-x _{1})\]
now what?
Now take one of those points and the slope and plug it into use slope intercept form
ok
You do this to find the y int which they call b in the formula \[y=mx+b\]
\[x _{1}=1,y _{1}=3,x _{2}=4,y _{2=4}\]
i got 2 2/3..
correct
so now its y=(1/3)x+2 2/3
thats my answer??
2 2/3 is C of the equation Ax+By=C and no thats not the answer yeet
ok
i have to plug that in for Ax + By = C ?
\[y-3=\frac{ 4-1 }{ 4-3 }(x-1)\]
now solve it
Remeber A, B, and C can't have fractions in them so after you move around the equation you get y=(1/3)x+ 2 2/3 subtract 1/3 x from both sides (-1/3)x+y= 2 2/3 multiply both sides by 3 to get rid of the fractions we get -x+3y=8 <-----
They usually don't have the x to be negative so really x-3y= -8 is a better answer
oh! okay i got it! thank youu!!
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