What is the center and radius of (x - 6)2 + (y + 1)2 = 81
\[\huge Welcome~To~Open~Study\] @2413
the radius is whatever the equation equals, just squared so: \[\sqrt{81}=?\] And yes, welcome
how do you make that big text? >.<
@Luigi0210 select the text (or fancy math expression), then right click and select Show Math As >TeX commands...
@2413 the formula for a circle with radius \(r\) and center \((h,k)\) is \[(x-h)^2+(y-k)^2=r^2\]Does that look similar to anything you have?
I'm using iPad
very painful doing OpenStudy on an iPad, I know!
The center is the vertex : (h,k) \[\large (x-h)^2 + (y-k)^2 = r^2\]your equation \[\large (x -\color{red}{6})^2+(y-\color{red}{(-1)})^2 = 81\]
and the radius is there at the end as r^2
and you can think of that \(r^2\) as \((\sqrt{81})^2\) so \(r = \sqrt{81}\)
I actually feel like Luigi right now >.<
what do you feel like when you aren't feeling like Luigi?
A normal person that isn't being ignored
Looks like we're all being ignored
I summon the powers of negative zone! time to dance :D
Join our real-time social learning platform and learn together with your friends!