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Mathematics 16 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

$$x^2-5x-6=(x-6)(x+1)\le 0$$So we know our function crosses the \(x\)-axis at \(x=-1,6\). Judging by the leading positive term, we know our function is a parabola oriented upward so in between and including our \(x\)-intercepts we're nonpositive:|dw:1371893817946:dw|

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