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Mathematics 7 Online
OpenStudy (anonymous):

explain this!

OpenStudy (anonymous):

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

@DLS @shamim @dan815 @jhonyy9

OpenStudy (anonymous):

guys help please!

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

@mathslover would you explain?

mathslover (mathslover):

@ganeshie8

mathslover (mathslover):

I am not sure for the correct method to solve this quest.

mathslover (mathslover):

50% Sure though...

OpenStudy (anonymous):

at least explain what you know! nobody is helping me! :/

mathslover (mathslover):

Okay, what is amount here?

OpenStudy (anonymous):

100

mathslover (mathslover):

Wait please...

OpenStudy (anonymous):

in 6 months time the amount will be 150 then for the other 6 months 150 will become our principal amount which would become 225 in one year so the 100 will double between 6 months and 1 year am i right?

ganeshie8 (ganeshie8):

thats perfect !

ganeshie8 (ganeshie8):

and a very good logic indeed :)

OpenStudy (anonymous):

thanks @ganeshie8 i was waiting for someone to help from so long !

ganeshie8 (ganeshie8):

np :) we may use compound interest formula also for this. but that would involve logs

OpenStudy (anonymous):

and i don't know that advance maths :P

OpenStudy (anonymous):

@mathslover thank you too, at least you tried to help :)

ganeshie8 (ganeshie8):

\(100(1+0.5)^t = 200\) \((1+0.5)^t = 2\) \(t = 1.7\) \(t = 1.7 \times 6 \) months

ganeshie8 (ganeshie8):

but the practical answer for this wud be "atleast one year" cuz banks wont deposit money to ur account until a full 6 months period completes.

OpenStudy (anonymous):

so the answer should be B then?

ganeshie8 (ganeshie8):

they update ur balance, oly after every 6 months. so you will see 200+ in ur bank account, oly after 1 year. eventhough, technically you would have earned the same in \(1.7 \times 6\) = 10.2 months.

ganeshie8 (ganeshie8):

I would tick B.

ganeshie8 (ganeshie8):

you can do this :- 1. if this q is from finance tick B 2. if this q is from math tick A either case check with your teacher what she wants :)

OpenStudy (anonymous):

ok i will take B as the answer then! but in the ques they have asked how long will it take the amount to double, not how long will it take to get the double amount? so don;t you think it will be A

mathslover (mathslover):

I was applying logs too.

OpenStudy (anonymous):

the problem is it is just a worksheet!

mathslover (mathslover):

But its complicated ...

ganeshie8 (ganeshie8):

yea i see you have a point there :) lets go with A :)

OpenStudy (anonymous):

ok then A it is :)

OpenStudy (anonymous):

one more thing it might be a dumb question but how did you solve for the power t in the above eq ?

ganeshie8 (ganeshie8):

its not dumb q lol :) ive used my calculator

mathslover (mathslover):

we can solve it without using calculator

OpenStudy (anonymous):

no i mean t was the power how did you turn it into a variable?

ganeshie8 (ganeshie8):

\((1+0.5)^t = 2 \) \(1.5^t = 2\) take log both sides

ganeshie8 (ganeshie8):

lets wait for mathslover :)

mathslover (mathslover):

\(A = P ( 1 + \cfrac{r}{100} ) ^{2 t}\) \(200 = 100 ( 1+ \cfrac{1}{2} ) ^{2t}\) \(2 = (\cfrac{9}{4})^t\) \(2^{2t + 1 } = 9^t\) \((2t+1) \log 2 = t \log 9 \) \((2t) \log 2 + \log 2 - t\log 9 = 0 \) \(t(2\log 2 - \log 9 ) = -\log 2\)

mathslover (mathslover):

From which I get : \(t = \cfrac{-\log 2}{ 2\log 2 - \log 9}\) \(t = \cfrac{- \log 2}{ \log (\cfrac{4}{9})}\) it is sure that t will be positive... (log (4/9) is negative) .. So, I am right yet... :)

mathslover (mathslover):

\(t = \cfrac{\log 2}{ \log (\cfrac{9}{4}) } \) \(t = \cfrac{\log 2}{ \log (2.25) }\) We can say that it approaches to 1... , So t can not be greater than 1 ,..

mathslover (mathslover):

That is it is option A)

mathslover (mathslover):

^ This is how I solved it :)

OpenStudy (anonymous):

good job, a bit technical for me but i got it!

mathslover (mathslover):

Though it can be solved in a better manner but my mind was not working at that time and is not working now also :)

mathslover (mathslover):

Farheen, logs are very interesting. I will suggest you to read some of the basics if you get time. And thanks :)

OpenStudy (anonymous):

nvrmind i now know two methods to solve it i know log i need to revise the property and if i need any help i will ask you :)

mathslover (mathslover):

Sure!

ganeshie8 (ganeshie8):

Nice deduction mathslover :)

mathslover (mathslover):

Thanks :)

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