Choose the equation that could be used to find two consecutive integers whose sum is 67.
n + (n + 2) = 67
n − (n + 1) = 67
n + n = 67
n + (n + 1) = 67
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OpenStudy (anonymous):
define consecutive
OpenStudy (anonymous):
Numbers which follow each other in order, without gaps, from smallest to largest.
OpenStudy (anonymous):
define sum
OpenStudy (anonymous):
add
OpenStudy (anonymous):
ok so if n is the starting number
the next consecutive number would be n+1, right?
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OpenStudy (anonymous):
i believe so
OpenStudy (anonymous):
so which one do you think is the answer
OpenStudy (anonymous):
b.
OpenStudy (anonymous):
what does sum mean again?
OpenStudy (anonymous):
O sorry i mean D.
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Ty :)
OpenStudy (anonymous):
It would be n+(n+1)=67
We know for 2 numbers to be consecutive, one has to be one more than the other (i.e. 1, and 2 are consecutive numbers, where 2 is 1 greater than 1)
So, n+(n+1)=67 will be applied :)
Now solve:
2n+1=67
2n=67-6
2n=66
n=66/2
n=33
So, the other number will be (x+1)=33+1=34
The first number is 33 and second is 34
I hope I'm clear :) if not then just lemme know I'll explain it again :)
OpenStudy (anonymous):
good job @xoya , however it never asked for n
OpenStudy (anonymous):
Thankyou :) I wanted to clear so I explained it :)
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