Question

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided.

Q + X yields products

Trial [Q] [X] Rate
1 0.12 M 0.10 M 1.5 × 10-3 M/min
2 0.24 M 0.10 M 3.0 × 10-3 M/min
3 0.12 M 0.20 M 12.0 × 10-3 M/min

Answer 1

You wanna look at 2 trials when only 1 of the substance's concentration changed.

so in trial 1 and 2 only [Q] changed.. notice that the rate increased by 2..
in trial 1 and 3 only [X] changed.. rate increased by by 8..

so find the exponents (a, b) on the rate law that describe this relationship.

\[\frac{ d[products] }{ dt }=rate=k[Q]^{a}[X]^{b}\]